(x+2)^2/5-7(x+2)^1/5+10

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Solution for (x+2)^2/5-7(x+2)^1/5+10 equation: 


x in (-oo:+oo)

((x+2)^2)/5-((7*(x+2)^1)/5)+10 = 0

((x+2)^2)/5+(-7/5)*(x+2)+10 = 0

((x+2)^2)/5-7/5*(x+2)+10 = 0

((x+2)^2)/5+(-7/5*5*(x+2))/5+(5*10)/5 = 0

(x+2)^2-7/5*5*(x+2)+5*10 = 0

x^2-3*x-10+50 = 0

x^2-3*x+40 = 0

x^2-3*x+40 = 0

x^2-3*x+40 = 0

DELTA = (-3)^2-(1*4*40)

DELTA = -151

DELTA < 0

1 = 0

1/5 = 0

1/5 = 0 // * 5

1 = 0

x belongs to the empty set

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